Integrand size = 18, antiderivative size = 139 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=\frac {5 b^2 (A b+6 a B) \sqrt {a+b x}}{8 a}-\frac {5 b (A b+6 a B) (a+b x)^{3/2}}{24 a x}-\frac {(A b+6 a B) (a+b x)^{5/2}}{12 a x^2}-\frac {A (a+b x)^{7/2}}{3 a x^3}-\frac {5 b^2 (A b+6 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{8 \sqrt {a}} \]
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Time = 0.04 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {79, 43, 52, 65, 214} \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=-\frac {5 b^2 (6 a B+A b) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{8 \sqrt {a}}+\frac {5 b^2 \sqrt {a+b x} (6 a B+A b)}{8 a}-\frac {(a+b x)^{5/2} (6 a B+A b)}{12 a x^2}-\frac {5 b (a+b x)^{3/2} (6 a B+A b)}{24 a x}-\frac {A (a+b x)^{7/2}}{3 a x^3} \]
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Rule 43
Rule 52
Rule 65
Rule 79
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {A (a+b x)^{7/2}}{3 a x^3}+\frac {\left (\frac {A b}{2}+3 a B\right ) \int \frac {(a+b x)^{5/2}}{x^3} \, dx}{3 a} \\ & = -\frac {(A b+6 a B) (a+b x)^{5/2}}{12 a x^2}-\frac {A (a+b x)^{7/2}}{3 a x^3}+\frac {(5 b (A b+6 a B)) \int \frac {(a+b x)^{3/2}}{x^2} \, dx}{24 a} \\ & = -\frac {5 b (A b+6 a B) (a+b x)^{3/2}}{24 a x}-\frac {(A b+6 a B) (a+b x)^{5/2}}{12 a x^2}-\frac {A (a+b x)^{7/2}}{3 a x^3}+\frac {\left (5 b^2 (A b+6 a B)\right ) \int \frac {\sqrt {a+b x}}{x} \, dx}{16 a} \\ & = \frac {5 b^2 (A b+6 a B) \sqrt {a+b x}}{8 a}-\frac {5 b (A b+6 a B) (a+b x)^{3/2}}{24 a x}-\frac {(A b+6 a B) (a+b x)^{5/2}}{12 a x^2}-\frac {A (a+b x)^{7/2}}{3 a x^3}+\frac {1}{16} \left (5 b^2 (A b+6 a B)\right ) \int \frac {1}{x \sqrt {a+b x}} \, dx \\ & = \frac {5 b^2 (A b+6 a B) \sqrt {a+b x}}{8 a}-\frac {5 b (A b+6 a B) (a+b x)^{3/2}}{24 a x}-\frac {(A b+6 a B) (a+b x)^{5/2}}{12 a x^2}-\frac {A (a+b x)^{7/2}}{3 a x^3}+\frac {1}{8} (5 b (A b+6 a B)) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right ) \\ & = \frac {5 b^2 (A b+6 a B) \sqrt {a+b x}}{8 a}-\frac {5 b (A b+6 a B) (a+b x)^{3/2}}{24 a x}-\frac {(A b+6 a B) (a+b x)^{5/2}}{12 a x^2}-\frac {A (a+b x)^{7/2}}{3 a x^3}-\frac {5 b^2 (A b+6 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{8 \sqrt {a}} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.69 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=-\frac {\sqrt {a+b x} \left (3 b^2 x^2 (11 A-16 B x)+4 a^2 (2 A+3 B x)+2 a b x (13 A+27 B x)\right )}{24 x^3}-\frac {5 b^2 (A b+6 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{8 \sqrt {a}} \]
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Time = 0.54 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.63
method | result | size |
pseudoelliptic | \(-\frac {11 \left (\frac {5 b^{2} x^{3} \left (A b +6 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{11}+\left (\frac {26 x b \left (\frac {27 B x}{13}+A \right ) a^{\frac {3}{2}}}{33}+\frac {4 \left (B x +\frac {2 A}{3}\right ) a^{\frac {5}{2}}}{11}+b^{2} x^{2} \sqrt {a}\, \left (-\frac {16 B x}{11}+A \right )\right ) \sqrt {b x +a}\right )}{8 \sqrt {a}\, x^{3}}\) | \(88\) |
risch | \(-\frac {\sqrt {b x +a}\, \left (33 A \,b^{2} x^{2}+54 B a b \,x^{2}+26 a A b x +12 a^{2} B x +8 a^{2} A \right )}{24 x^{3}}+\frac {b^{2} \left (32 B \sqrt {b x +a}-\frac {2 \left (5 A b +30 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\right )}{16}\) | \(93\) |
derivativedivides | \(2 b^{2} \left (B \sqrt {b x +a}-\frac {\left (\frac {11 A b}{16}+\frac {9 B a}{8}\right ) \left (b x +a \right )^{\frac {5}{2}}+\left (-\frac {5}{6} a b A -2 a^{2} B \right ) \left (b x +a \right )^{\frac {3}{2}}+\left (\frac {7}{8} a^{3} B +\frac {5}{16} a^{2} b A \right ) \sqrt {b x +a}}{b^{3} x^{3}}-\frac {5 \left (A b +6 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{16 \sqrt {a}}\right )\) | \(109\) |
default | \(2 b^{2} \left (B \sqrt {b x +a}-\frac {\left (\frac {11 A b}{16}+\frac {9 B a}{8}\right ) \left (b x +a \right )^{\frac {5}{2}}+\left (-\frac {5}{6} a b A -2 a^{2} B \right ) \left (b x +a \right )^{\frac {3}{2}}+\left (\frac {7}{8} a^{3} B +\frac {5}{16} a^{2} b A \right ) \sqrt {b x +a}}{b^{3} x^{3}}-\frac {5 \left (A b +6 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{16 \sqrt {a}}\right )\) | \(109\) |
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Time = 0.24 (sec) , antiderivative size = 229, normalized size of antiderivative = 1.65 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=\left [\frac {15 \, {\left (6 \, B a b^{2} + A b^{3}\right )} \sqrt {a} x^{3} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (48 \, B a b^{2} x^{3} - 8 \, A a^{3} - 3 \, {\left (18 \, B a^{2} b + 11 \, A a b^{2}\right )} x^{2} - 2 \, {\left (6 \, B a^{3} + 13 \, A a^{2} b\right )} x\right )} \sqrt {b x + a}}{48 \, a x^{3}}, \frac {15 \, {\left (6 \, B a b^{2} + A b^{3}\right )} \sqrt {-a} x^{3} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (48 \, B a b^{2} x^{3} - 8 \, A a^{3} - 3 \, {\left (18 \, B a^{2} b + 11 \, A a b^{2}\right )} x^{2} - 2 \, {\left (6 \, B a^{3} + 13 \, A a^{2} b\right )} x\right )} \sqrt {b x + a}}{24 \, a x^{3}}\right ] \]
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Time = 59.84 (sec) , antiderivative size = 348, normalized size of antiderivative = 2.50 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=- \frac {A a^{3}}{3 \sqrt {b} x^{\frac {7}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {17 A a^{2} \sqrt {b}}{12 x^{\frac {5}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {35 A a b^{\frac {3}{2}}}{24 x^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {A b^{\frac {5}{2}} \sqrt {\frac {a}{b x} + 1}}{\sqrt {x}} - \frac {3 A b^{\frac {5}{2}}}{8 \sqrt {x} \sqrt {\frac {a}{b x} + 1}} - \frac {5 A b^{3} \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{8 \sqrt {a}} - \frac {7 B \sqrt {a} b^{2} \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{4} - \frac {B a^{3}}{2 \sqrt {b} x^{\frac {5}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {3 B a^{2} \sqrt {b}}{4 x^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}} - \frac {2 B a b^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}}{\sqrt {x}} - \frac {B a b^{\frac {3}{2}}}{4 \sqrt {x} \sqrt {\frac {a}{b x} + 1}} + B b^{2} \left (\begin {cases} \frac {2 a \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{\sqrt {- a}} + 2 \sqrt {a + b x} & \text {for}\: b \neq 0 \\\sqrt {a} \log {\left (x \right )} & \text {otherwise} \end {cases}\right ) \]
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Time = 0.28 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.21 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=\frac {1}{48} \, b^{3} {\left (\frac {96 \, \sqrt {b x + a} B}{b} + \frac {15 \, {\left (6 \, B a + A b\right )} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{\sqrt {a} b} - \frac {2 \, {\left (3 \, {\left (18 \, B a + 11 \, A b\right )} {\left (b x + a\right )}^{\frac {5}{2}} - 8 \, {\left (12 \, B a^{2} + 5 \, A a b\right )} {\left (b x + a\right )}^{\frac {3}{2}} + 3 \, {\left (14 \, B a^{3} + 5 \, A a^{2} b\right )} \sqrt {b x + a}\right )}}{{\left (b x + a\right )}^{3} b - 3 \, {\left (b x + a\right )}^{2} a b + 3 \, {\left (b x + a\right )} a^{2} b - a^{3} b}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.09 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=\frac {48 \, \sqrt {b x + a} B b^{3} + \frac {15 \, {\left (6 \, B a b^{3} + A b^{4}\right )} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} - \frac {54 \, {\left (b x + a\right )}^{\frac {5}{2}} B a b^{3} - 96 \, {\left (b x + a\right )}^{\frac {3}{2}} B a^{2} b^{3} + 42 \, \sqrt {b x + a} B a^{3} b^{3} + 33 \, {\left (b x + a\right )}^{\frac {5}{2}} A b^{4} - 40 \, {\left (b x + a\right )}^{\frac {3}{2}} A a b^{4} + 15 \, \sqrt {b x + a} A a^{2} b^{4}}{b^{3} x^{3}}}{24 \, b} \]
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Time = 0.45 (sec) , antiderivative size = 182, normalized size of antiderivative = 1.31 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^4} \, dx=\frac {\left (\frac {11\,A\,b^3}{8}+\frac {9\,B\,a\,b^2}{4}\right )\,{\left (a+b\,x\right )}^{5/2}+\left (\frac {7\,B\,a^3\,b^2}{4}+\frac {5\,A\,a^2\,b^3}{8}\right )\,\sqrt {a+b\,x}-\left (4\,B\,a^2\,b^2+\frac {5\,A\,a\,b^3}{3}\right )\,{\left (a+b\,x\right )}^{3/2}}{3\,a\,{\left (a+b\,x\right )}^2-3\,a^2\,\left (a+b\,x\right )-{\left (a+b\,x\right )}^3+a^3}+2\,B\,b^2\,\sqrt {a+b\,x}-\frac {5\,b^2\,\mathrm {atanh}\left (\frac {5\,b^2\,\left (A\,b+6\,B\,a\right )\,\sqrt {a+b\,x}}{4\,\sqrt {a}\,\left (\frac {5\,A\,b^3}{4}+\frac {15\,B\,a\,b^2}{2}\right )}\right )\,\left (A\,b+6\,B\,a\right )}{8\,\sqrt {a}} \]
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